{"id":23329,"date":"2023-03-28T20:15:10","date_gmt":"2023-03-28T20:15:10","guid":{"rendered":"https:\/\/blogs.ugto.mx\/rea\/?p=23329"},"modified":"2023-03-28T20:45:29","modified_gmt":"2023-03-28T20:45:29","slug":"clase-digital-10-leyes-de-kirchhoff","status":"publish","type":"post","link":"https:\/\/blogs.ugto.mx\/rea\/clase-digital-10-leyes-de-kirchhoff\/","title":{"rendered":"Clase digital 10. Leyes de Kirchhoff"},"content":{"rendered":"\n\n\n<div class=\"wp-block-cover\" style=\"min-height:284px;aspect-ratio:unset;\"><span aria-hidden=\"true\" class=\"wp-block-cover__background has-background-dim-40 has-background-dim\"><\/span><img decoding=\"async\" class=\"wp-block-cover__image-background wp-image-23453\" alt=\"\" src=\"data:image\/gif;base64,R0lGODlhAQABAIAAAAAAAP\/\/\/yH5BAEAAAAALAAAAAABAAEAAAIBRAA7\" data-src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/pexels-pok-rie-1432680.jpg\" style=\"object-position:46% 84%\" data-object-fit=\"cover\" data-object-position=\"46% 84%\" \/><noscript><img loading=\"lazy\" decoding=\"async\" width=\"1279\" height=\"853\" class=\"wp-block-cover__image-background wp-image-23453\" alt=\"\" src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/pexels-pok-rie-1432680.jpg\" style=\"object-position:46% 84%\" data-object-fit=\"cover\" data-object-position=\"46% 84%\" srcset=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/pexels-pok-rie-1432680.jpg 1279w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/pexels-pok-rie-1432680-300x200.jpg 300w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/pexels-pok-rie-1432680-1024x683.jpg 1024w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/pexels-pok-rie-1432680-768x512.jpg 768w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/pexels-pok-rie-1432680-272x182.jpg 272w\" sizes=\"auto, (max-width: 1279px) 100vw, 1279px\" \/><\/noscript><div class=\"wp-block-cover__inner-container is-layout-flow wp-block-cover-is-layout-flow\">\n<p class=\"has-text-align-center has-base-3-color has-text-color has-large-font-size wp-block-paragraph\">Leyes de Kirchhoff<\/p>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"introduccion\">Introducci\u00f3n<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">En esta lecci\u00f3n estudiaremos las leyes de Kirchhoff que ampliar\u00e1n nuestras habilidades y herramientas para resolver circuitos el\u00e9ctricos en los cuales no es suficiente con la aplicaci\u00f3n simple de la ley de Ohm. Por otro lado, el uso de las leyes de Kirchhoff nos permitir\u00e1n comprobar nuestros resultados e incluso entender de mejor manera las estrategias y t\u00e1cticas para resolver circuitos el\u00e9ctricos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Estudia con \u00e1nimo y gusto. Este tema ampliar\u00e1 tus conocimientos y facilitar\u00e1 tu aprendizaje y comprensi\u00f3n.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u00a1Iniciemos nuestro estudio! \u00a1Vamos con todo!<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"desarrollo-del-tema\">Desarrollo del tema <\/h2>\n\n\n\n<h3 class=\"wp-block-heading\">Leyes de Kirchhoff<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">En el siglo IXX el cient\u00edfico alem\u00e1n Gustav Robert Kirchhoff, estudioso de la Electricidad, propuso dos reglas para analizar circuitos el\u00e9ctricos complejos, en los que ya no resulta tan sencillo aplicar la ley de Ohm.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Primera ley de Kirchhoff<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">\u201cLa suma de todas las intensidades de corriente que llegan a un nodo de un circuito es igual a la suma de todas las intensidades de corriente que salen de \u00e9l.\u201d (Montiel, 2015:424)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">En un circuito el\u00e9ctrico, a cualquier punto en el que concurren 3 o m\u00e1s conductores se le conoce como nodo. En la figura 10.1. el punto A es un nodo y si aplicamos la primera ley de Kirchhoff, se cumple que<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img decoding=\"async\" src=\"data:image\/gif;base64,R0lGODlhAQABAIAAAAAAAP\/\/\/yH5BAEAAAAALAAAAAABAAEAAAIBRAA7\" data-src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.52.03.png\" alt=\"\" class=\"wp-image-23448\" \/><noscript><img loading=\"lazy\" decoding=\"async\" width=\"891\" height=\"63\" src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.52.03.png\" alt=\"\" class=\"wp-image-23448\" srcset=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.52.03.png 891w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.52.03-300x21.png 300w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.52.03-768x54.png 768w\" sizes=\"auto, (max-width: 891px) 100vw, 891px\" \/><\/noscript><\/figure>\n<\/div>\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img decoding=\"async\" src=\"data:image\/gif;base64,R0lGODlhAQABAIAAAAAAAP\/\/\/yH5BAEAAAAALAAAAAABAAEAAAIBRAA7\" data-src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.53.01.png\" alt=\"\" class=\"wp-image-23449\" \/><noscript><img loading=\"lazy\" decoding=\"async\" width=\"648\" height=\"372\" src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.53.01.png\" alt=\"\" class=\"wp-image-23449\" srcset=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.53.01.png 648w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-9.53.01-300x172.png 300w\" sizes=\"auto, (max-width: 648px) 100vw, 648px\" \/><\/noscript><figcaption class=\"wp-element-caption\"><strong>Imagen 1.<\/strong> La corriente I que llega al nodo A se divide en I<sub>1<\/sub> e I<sub>2<\/sub>.<br><\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Los videos a continuaci\u00f3n te explican el concepto de la primera ley de Kirchhoff y se resuelven algunos ejemplos:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Primera ley de Kirchhoff.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"PRIMERA LEY DE KIRCHHOFF - EJERCICIO RESUELTO # 1\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/T0cKvbxsoeY?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">2. Ejercicio primer ley de Kirchhoff.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Primera Ley de Kirchhoff\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/u5_OPR46G7Q?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Ejercicio resuelto de la primer ley de Kirchhoff.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"PRIMERA LEY DE KIRCHHOFF NODOS ll PRIMERA LEY DE KIRCHHOFF EJERCICIOS RESUELTOS 2\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/-onciloIIAI?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<h4 class=\"wp-block-heading\">Segunda ley de Kirchhoff<\/h4>\n\n\n\n<p class=\"wp-block-paragraph\">La segunda ley de Kirchhoff, seg\u00fan Montiel P., H. (2015:427), establece que la suma de las ca\u00eddas de tensi\u00f3n IR en una malla o circuito cerrado es igual al voltaje total que se aplica al circuito. Esto es, que la suma de las fem&nbsp;\u2211\u2107 en un circuito cerrado o malla es igual a la sumatoria de todas las ca\u00eddas de tensi\u00f3n IR en el circuito, lo cual queda expresado como<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img decoding=\"async\" src=\"data:image\/gif;base64,R0lGODlhAQABAIAAAAAAAP\/\/\/yH5BAEAAAAALAAAAAABAAEAAAIBRAA7\" data-src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.50.52.png\" alt=\"\" class=\"wp-image-23450\" \/><noscript><img loading=\"lazy\" decoding=\"async\" width=\"920\" height=\"49\" src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.50.52.png\" alt=\"\" class=\"wp-image-23450\" srcset=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.50.52.png 920w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.50.52-300x16.png 300w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.50.52-768x41.png 768w\" sizes=\"auto, (max-width: 920px) 100vw, 920px\" \/><\/noscript><\/figure>\n<\/div>\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img decoding=\"async\" src=\"data:image\/gif;base64,R0lGODlhAQABAIAAAAAAAP\/\/\/yH5BAEAAAAALAAAAAABAAEAAAIBRAA7\" data-src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.51.51.png\" alt=\"\" class=\"wp-image-23451\" \/><noscript><img loading=\"lazy\" decoding=\"async\" width=\"915\" height=\"287\" src=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.51.51.png\" alt=\"\" class=\"wp-image-23451\" srcset=\"https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.51.51.png 915w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.51.51-300x94.png 300w, https:\/\/blogs.ugto.mx\/rea\/wp-content\/uploads\/sites\/71\/2023\/03\/Captura-de-Pantalla-2023-03-07-a-las-10.51.51-768x241.png 768w\" sizes=\"auto, (max-width: 915px) 100vw, 915px\" \/><\/noscript><figcaption class=\"wp-element-caption\"><strong>Imagen 2. <\/strong>Segunda ley de Kirchhoff.<\/figcaption><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Para la fig. 10.2 se cumple en el a) que V<sub>T<\/sub>=V<sub>1<\/sub>+V<sub>2<\/sub>+V<sub>3<\/sub>=12 V y en b) V<sub>T<\/sub>=V<sub>3<\/sub>=6 V o V<sub>T<\/sub>=V<sub>1<\/sub>+V<sub>2<\/sub>=6 V.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Enseguida te incluyo videos de la 2da ley de Kirchhoff:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Segunda ley de Kirchhoff problemas resueltos.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Leyes de Kirchhoff-2da. Ley (m\u00e9todo de malla)\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/QVOCCVv-bJA?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Segunda ley de Kirchhoff y problemas resueltos.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"EJERCICIOS DE LA SEGUNDA LEY DE KIRCHHOFF # 2\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/Eigl_iZLcBk?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Complementa tu aprendizaje sobre las leyes de Kirchhoff con los siguientes videos:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Leyes de Kirchhoff circuito en paralelo.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Leyes de Kirchhoff circuito paralelo\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/3BBeD37EAUQ?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Leyes de Kirchhoff circuito en serie.<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Electricista E1 C7 Leyes de Kirchoff &#039;Circuito en serie&#039;1\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/5X91eGYbVlk?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Leyes de Kirchhoff<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Leyes de Kirchhoff. Soluci\u00f3n de un Circuito.\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/Ni37_i656RI?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption class=\"wp-element-caption\"><br>Leyes de Kirchhoff. Ejercicio resuelto<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"\u26a1 Leyes de Kirchhoff \u26a1. Mallas y nudos. Ejercicio circuito resuelto paso a paso \ud83d\udca5\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/3w2VrXKh5h4?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"conclusion\">Conclusi\u00f3n<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Hemos aprendido a usar las leyes de Kirchhoff para calcular las corrientes y los voltajes en los circuitos o mallas el\u00e9ctricas. El hecho de saber que deben ser iguales la suma de corrientes entrantes y salientes a un nodo debe nos ayuda a comprobar nuestros resultados cuando estamos resolviendo un circuito de resistores de este tipo. Es el mismo caso con los voltajes, esto es, que si en cualquier malla cerrada se cumple que la suma de fem es igual a la suma de las ca\u00eddas de tensi\u00f3n, esto nos puede apoyar para revisar y comprobar que nuestras soluciones son congruentes.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Te invito a revisar los pdf que se encuentran en las fuentes de informaci\u00f3n; su estudio te apoyar\u00e1 en caso de dudas o si quisieras profundizar en tus aprendizajes.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u00a1Siento que vas bien! Te invito a continuar con gusto y compromiso. En la siguiente lecci\u00f3n iniciamos con el estudio del Electromagnetismo.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Vamos hacia adelante!<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"fuentes-de-informacion\">Fuentes de informaci\u00f3n<\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Tippens, P. (2011). <a href=\"https:\/\/drive.google.com\/file\/d\/1I8Qyxm06IXRd6FxNaEby04qikb3vhGnN\/view?usp=sharing\" target=\"_blank\" rel=\"noreferrer noopener nofollow\">Circuitos de corriente continua. En Edamsa Impresiones<\/a> (Ed.), F\u00edsica Conceptos y aplicaciones, (p.556-562). Mc Graw Hill.<\/li>\n\n\n\n<li>P\u00e9rez M., H. (2015). <a href=\"https:\/\/drive.google.com\/file\/d\/154rmKUvciHYI_Ooo4uP_hTTR3HXvD7V8\/view?usp=sharing\" target=\"_blank\" rel=\"noreferrer noopener nofollow\">Leyes de Kirchhoff, F\u00edsica General<\/a> (p.424-428). Grupo Editorial Patria<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Introducci\u00f3n En esta lecci\u00f3n estudiaremos las leyes de Kirchhoff que ampliar\u00e1n nuestras habilidades y herramientas para resolver circuitos el\u00e9ctricos en los cuales no es suficiente con la aplicaci\u00f3n simple de la ley de Ohm. Por otro lado, el uso de las leyes de Kirchhoff nos permitir\u00e1n comprobar nuestros resultados e incluso entender de mejor manera &#8230; <a title=\"Clase digital 10. Leyes de Kirchhoff\" class=\"read-more\" href=\"https:\/\/blogs.ugto.mx\/rea\/clase-digital-10-leyes-de-kirchhoff\/\" aria-label=\"Leer m\u00e1s sobre Clase digital 10. Leyes de Kirchhoff\">Leer m\u00e1s<\/a><\/p>\n","protected":false},"author":142,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","episode_type":"","audio_file":"","podmotor_file_id":"","podmotor_episode_id":"","cover_image":"","cover_image_id":"","duration":"","filesize":"","filesize_raw":"","date_recorded":"","explicit":"","block":"","itunes_episode_number":"","itunes_title":"","itunes_season_number":"","itunes_episode_type":"","footnotes":""},"categories":[339,617],"tags":[41,451,621],"class_list":["post-23329","post","type-post","status-publish","format-standard","hentry","category-bachillerato-plan-de-estudios-2020","category-uda-electromagnetismo-bachillerato-plan-de-estudios-2020","tag-clase-digital","tag-juan-tinoco-villagomez-2","tag-neba04012"],"acf":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/posts\/23329","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/users\/142"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/comments?post=23329"}],"version-history":[{"count":4,"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/posts\/23329\/revisions"}],"predecessor-version":[{"id":23576,"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/posts\/23329\/revisions\/23576"}],"wp:attachment":[{"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/media?parent=23329"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/categories?post=23329"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.ugto.mx\/rea\/wp-json\/wp\/v2\/tags?post=23329"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}